• 有几点需要注意的地方一是将right转化为与left在在同一节

while (left + 4 <= right){    right -= 4;//每次将right移动4位，直到left与right在同一节}

• 二是输出的时候每一节中的位，以及后面的亿和万

参考代码：

#define _CRT_SECURE_NO_WARNINGS#include
    
     #include
     
      #include
      
       char num[10][5] = { "ling","yi","er","san","si","wu","liu","qi","ba","jiu" };char wei[5][5] = { "Shi","Bai","Qian","Wan","Yi" };int main(){    char str[15];    scanf("%s", str);//按字符串输入数字    int len = strlen(str);    int left = 0, right = len - 1;//分别指向字符串的首尾元素    if (str[0] == '-')    {        printf("Fu");        left++;    }    while (left + 4 <= right)    {        right -= 4;//每次将right移动4位，直到left与right在同一节    }    while (left < len)    {        bool flag = false;//flag==false表示没有累计的0                while (left <= right)        {            if (left > 0 && str[left] == '0')            {                flag = true;            }            else            {                if (flag == true)                {                    printf(" ling");                    flag = false;                }                if (left > 0) printf(" ");//只要不是首位都要在每个后面输出空格                printf("%s", num[str[left] - '0']);//输出当前位数字                                if (left != right)                {                    printf(" %s", wei[right - left - 1]);                }            }            left++;        }        if (right != len - 1)        {            printf(" %s", wei[(len - 1 - right) / 4 + 2]);        }        right += 4;    }    system("pause");    return 0;}